## Question

The current-gain of a transistor in a common-base arrangement is 0.98. Find the change in collector-current corresponding to a change of 5.0 mA in emitter-current. What would be the change in the base-current?

### Solution

4.9 m*A*, 0.1 m*A*

By definition, the *a*-*c* current-gain in common-base arrangement of a transistor is give by

= 4.9 m*A*.

We know that the base-current is emitter-current minus collector-current, that is

= 0.1 m*A*.

#### SIMILAR QUESTIONS

The value of from factor of full wave rectifier is

When the *p*-end of the *p*-*n* junction is connected to the negative terminal of the battery and the *n*-end to the positive terminal of the battery, then the*p*-*n* junction behaves like :

*n*-type semiconductor is formed :

An *n*-type and a *p*-type silicon can be obtained by doping pure silicon with :

An *n*-type semiconductor is :

The drift current in a *p*-*n* junction is :

The diffusion current in a *p*-*n* junction is

In a *p*-*n*-*p* transistor with normal bias:

The base-current of a transistor is and the collector-current is 2.05 mA. A change of in the base-current produces a change of 0.65 mA in the collector current. Find .

In a common-base amplifier the load-resistance of the output circuit is and the resistance of the input circuit is . If current-gain be 0.95, calculate the voltage-gain and the power gain.